What is the greatest number of 4 digits that which when divided by any of the numbers 6, 9, 12 and 17 leaves a remainder of 1?

9997

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9793

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9895

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9487

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Solution

The correct option is B 9793
$L . C . M o f 6, 9, 12, 17 = 612$
Largest 4 digit number which is divisible by 612 is 9792
Now adding reminder 1 will get Largest 4 digit number will be 9792+1 = 9793

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