What is the half-life of the first order reaction CH3CHO(g)→CH4(g)+CO(g), if an initial pressure of CH3CHO(g) is 80 mm and the total pressure at the end of 20 minutes is 120 mm?
A
80 min
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B
120 min
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C
20 min
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D
40 min
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Solution
The correct option is C 20 min The inital presure of CH3CHO(g) is 80 mm. After 20 minutes, let x be the change in the pressure of CH3CHO(g). Total pressure will be (P0−x)+x+x=P0+x=80+x=120mmHg Hence, x=40mm. Thus the pressure of CH3CHO(g) after 20 min is reduced to 80−40=40mm. Thus it is reduced to half. Thus 20 min is the half life period.