What is the HCF of $3.0, 1.2$ and $0.06$ ?

0.6

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0.06

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6.0

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6.06

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Solution

The correct option is A $0.06$
The given terms are $\frac{3}{1}, \frac{6}{5}$ and $\frac{3}{50}$ .
H.C.F. of these terms $= \frac{H.C.F. of 3, 6, 3}{L.C.M. of 1, 5, 50}$
$= \frac{3}{50} = 0.06$

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