What is the HCF of 4x3+3x2y−9xy2+2y3 and x2+xy−2y2?
A
x−2y
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
x−y
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
(x+2y)(x−y)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
(x−2y)(x−y)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C(x+2y)(x−y) Let f(x,y)=4x2+3x2y−9xy2+2y3 and g(x,y)=x2+xy−2y2 Clearly (x−y)=0 or x=y satisfy both equation, since for x=y makes both equations zero.
Hence, (x−y) is the H.C.F.
Similarly (x+2y)=0 i.e., x=−2y also makes both equations zero.