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Question

What is the HCF of 4x3+3x2y−9xy2+2y3 and x2+xy−2y2?

A
x2y
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B
xy
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C
(x+2y)(xy)
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D
(x2y)(xy)
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Solution

The correct option is C (x+2y)(xy)
Let f(x,y)=4x2+3x2y9xy2+2y3
and g(x,y)=x2+xy2y2
Clearly (xy)=0 or x=y satisfy both equation, since for x=y makes both equations zero.
Hence, (xy) is the H.C.F.
Similarly (x+2y)=0 i.e., x=2y also makes both equations zero.
Thus, (x+2y)(xy) is the H.C.F.

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