What is the HCF of 4 * 27 * 3125 , 8* 9 * 25 * 7 and 16 * 81 * 5 * 11 * 49
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Solution

Answer :

HCF of 4 $\times$ 27 $\times$ 3125 , 8 $\times$ 9 $\times$ 25 $\times$ 7 and 16 $\times$ 81 $\times$ 5 $\times$ 11 $\times$ 49

4 $\times$ 27 $\times$ 3125 = 2 $\times$ 2 $\times$ 3 $\times$ 3 $\times$ 3 $\times$ 5 $\times$ 5 $\times$ 5 $\times$ 5 $\times$ 5 ,

8 $\times$ 9 $\times$ 25 $\times$ 7 = 2 $\times$ 2 $\times$ 2 $\times$ 3 $\times$ 3 $\times$ 5 $\times$ 5 $\times$ 7

And

16 $\times$ 81 $\times$ 5 $\times$ 11 $\times$ 49 = 2 $\times$ 2 $\times$ 2 $\times$ 2 $\times$ 3 $\times$ 3 $\times$ 3 $\times$ 3 $\times$ 5 $\times$ 11 $\times$ 7 $\times$ 7

So,

HCF ( 4 $\times$ 27 $\times$ 3125 , 8 $\times$ 9 $\times$ 25 $\times$ 7 and 16 $\times$ 81 $\times$ 5 $\times$ 11 $\times$ 49 ) = 2 $\times$ 2 $\times$ 3 $\times$ 3 $\times$ 5 $\times$ 7

HCF ( 4 $\times$ 27 $\times$ 3125 , 8 $\times$ 9 $\times$ 25 $\times$ 7 and 16 $\times$ 81 $\times$ 5 $\times$ 11 $\times$ 49 ) = 4 $\times$ 9 $\times$ 5 $\times$ 7 ( Ans )

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Similar questions

4 \times 27 \times 3125, 8 \times 9 \times 25 \times 7, 16 \times 81 \times 5 \times 11 \times 49 ?

4 \times 27 \times 3125, 8 \times 9 \times 25 \times 7

16 \times 81 \times 5 \times 11 \times 49

The H.C.F. of 4 $\times$ 27 $\times$ 3125, 8 $\times$ 9 $\times$ 25 $\times$ 7 & 16 $\times$ 81 $\times$ 5 $\times$ 11 $\times$ 49 is ____.

Re-arrange suitably and find the sum in each of the following :

(i) $\frac{11}{12} + \frac{- 17}{3} + \frac{11}{2} + \frac{- 25}{2}$

(ii) $\frac{- 6}{7} + \frac{- 5}{6} + \frac{- 4}{9} + \frac{- 15}{7}$

(iii) $\frac{3}{5} + \frac{7}{3} + \frac{9}{5} + \frac{- 13}{15} + \frac{- 7}{3}$

(iv) $\frac{4}{13} + \frac{- 5}{8} + \frac{- 8}{13} + \frac{9}{13}$

(v) $\frac{2}{3} + \frac{- 4}{5} + \frac{1}{3} + \frac{2}{5}$

(vi) $\frac{1}{8} + \frac{5}{12} + \frac{2}{7} + \frac{7}{12} + \frac{9}{7} + \frac{- 5}{16}$

A = {1, 3, 5, 7, 9, 11},

B = {3, 9, 27, 81, 243},

n [(A \times B) \cap (B \times A)]

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