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Question

What is the HCF of two even consecutive numbers.


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Solution

Consider two consecutive even numbers. They are of the form 2n,2n+2 for some integer n

2n=2×n

2n+2=2×(n+1)

The numbers n,n+1, being two consecutive integers, are relatively prime

They do not have any factor other than 1 common to them.

Hence HCF of two consecutive even numbers is 2.


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