Question

What is the hybridisation state of xenon in $XeO{F}_4$?

• A. $s{p}^3$
• B. $s{p}^{3}d$
• C. $s{p}^3{d}^2$
• D. $s{p}^3{d}^3$

Answer 1

The correct option is C $s{p}^3{d}^2$

in ${XeOF}_4$,

Sigma bond=5

Pi bond=1

Lone pair=1

Adding sigma bond and lone pair we get 5+1=6

So, $Xe$ will need its s-orbital, three p-orbitals and two of its d-orbitals.

So, the hybridization will be ${sp}^3{d}^2$.

So, the correct answer is option C.