Question

What is the hybridization of $C$ atom in $C{H}_3$ radical?

• A. $s{p}^2$
• B. $s{p}^3$
• C. $sp$
• D. $s{p}^{3}d$

Answer 1

The correct option is A $s{p}^2$

$C$ has four electrons in its valence shell. In $C{H}_3$ radical, $C$ atom makes three sigma bonds with three $H$ atoms and have one unpaired electron. This unpaired electron does not take part in hybridization due to the low electronegativity of $H$ atom than central $C$ atom.
Therefore, the hybridization of $C$ atom in $C{H}_3$ radical will be $s{p}^2$.