Question

What is the hybridization of ${\left[CO\right(N{H}_3{)}_6]}^{3+}$?

• A. $s{p}^3$
• B. $d^{2}s{p}^3$
• C. $s{p}^{3}d$
• D. $ds{p}^3$

Answer 1

Answer: (B)

$d^{2}s{p}^3$

${\left[CO{\left(NH\right)}_6\right]}^{3+}$ is a inner orbital complex.

For this complex action the $6$ valance electrons of cobalt will occupy the $3d$ orbital, whereas the $6$ ligands will occupy $3d,4s$ and $4p$ orbitals in $d^2{sp}^3$ hybridisation.