Question

What is the hybridization of P in $PC{l}_5\left(\text{s}\right)$ ?

• A. $s{p}^3,s{p}^3{d}^2$
• B. $s{p}^{3}d,s{p}^{3}d$
• C. $s{p}^3,s{p}^3$
• D. $s{p}^{3}d,s{p}^3{d}^2$

Answer 1

The correct option is A

$s{p}^3,s{p}^3{d}^2$

In the solid state $PC{l}_5$ exists as an ionic compound made up $PC{l}_4^{+}$ (tetrahedral) and $PC{l}_6^{-}$ (octahedral) ions.

$PC{l}_5\left(\text{s}\right)\to \underset{\left(s{p}^3\right)}{[PC{l}_4{]}^{+}}\underset{\left(s{p}^3{d}^2\right)}{[PC{l}_6{]}^{-}}$