Question

What is the hybridization of sulphur in its crown ring structure?

• A. $sp$
• B. $s{p}^2$
• C. $s{p}^3$
• D. $s{p}^{3}d$

Answer 1

The correct option is C $s{p}^3$

• Hybridization of atom in molecules can be predictable by VSEPR theory.
• The structure of crown sulphur is:

$lonepairs=2$
$bondpairs=2$
$totalelectronpairs=4$

so according to VSEPR

total electron pairs	lone pairs	bond pairs	hybridization
2	0	2	$sp$
3	1	2	$s{p}^3$
4	0	4	$s{p}^3$
4	1	3	$s{p}^3$
4	2	2	$s{p}^3$
5	0	5	$s{p}^{3}d$
5	1	4	$s{p}^{3}d$

Thus, the hybridization of sulphur is $s{p}^3$