Question

What is the Hybridization of the Central atom in $\mathrm{NOBr}$?

Answer 1

1. The central atom in $\mathrm{NOBr}$ is N.
2. The electronic configuration of Nitrogen is $1{\mathrm{s}}^{2}2{\mathrm{s}}^{2}2{\mathrm{p}}^3$.

Calculation of Hybridization of $\mathrm{NOBr}$

Formula used-$\mathrm{Steric}\mathrm{number}=\mathrm{lone}\mathrm{pair}+\mathrm{bond}\mathrm{pair}$

Bond pair=2

lone pair=1

By substituting the values in the formula

$$\begin{gathered} \mathrm{Steric}\mathrm{number}=1+2 \\ \mathrm{Steric}\mathrm{number}=3 \end{gathered}$$

Thus the hybridization of $\mathrm{NOBr}$ is ${\mathrm{sp}}^2$and the shape is trigonal bipyramidal.