What is the hybridization state of carbon number $2$ and $3$ in the following compound $C H_{2} = C H - C \equiv C H$

s p

and

s p^{2}

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s p^{2}

and

s p

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s p^{3}

and

s p

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s p

and

s p

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Solution

The correct option is B $s p^{2}$ and $s p$
Second carbion is $S P_{2}$ hybridised as it has double bond and 3 carbon is $S P$ hybridised as it has triple bond

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