What is the hybridization type of N atom in $N H_{3}$ ?

s p

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s p^{2}

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s p^{3} d

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s p^{3}

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Solution

The correct option is D $s p^{3}$
In Ammonia $(N H_{3})$ or to be more precise the central atom in ammonia which is nitrogen is $s p^{3}$ hybridized.
During the formation of ammonia, one $2 s$ orbital and three $2 p$ orbitals of nitrogen combine to form four hybrid orbitals having equivalent energy which is then considered as an $s p^{3}$ type of hybridization.

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Question 03

The types of hybrid orbitals of nitrogen in $N O_{2}^{+}, N O_{3}^{-} a n d N H_{4}^{+}$ respectively are expected to be

(a) $s p, s p^{3} a n d s p^{2}$

(b) $s p, s p^{2} a n d s p^{3}$

(d) $s p^{2}, s p^{3} a n d s p$

The correct order of hybridization of the central atom in the following species $N H_{3}, [P t C l_{4}]^{2 -}$ , $P C l_{5}$ and $B C l_{3}$ is

L i H + {B - -}_{2} H_{6} \to 2 L i B - - H_{4}

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