What is the increasing order of equivalent weights of the following oxidising agents? (i) KMnO4⟶Mn2+ (ii) K2Cr2O7⟶Cr3+ (iii) KClO3⟶Cl− [Atomic wt.: K=39,Cr=52,Mn=55,Cl=35.5,O=16]
A
KClO3<KMnO4<K2Cr2O7
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B
K2Cr2O7<KMnO4<KClO3
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C
KMnO4<K2Cr2O7<KClO3
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D
KClO3<K2Cr2O7<KMnO4
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Solution
The correct option is AKClO3<KMnO4<K2Cr2O7 (i)K7+MnO4⟶Mn2+⇒E1=39+55+645=31.6 (ii)K26+Cr2O7⟶Cr3+⇒E2=39×2+52×2+16×76=49 (iii)K5+ClO3⟶Cl− ⇒E3=39+35.5+486=20.4