What is the inradius of a regular hexagon of sides 6 cm?
3√3 cm
In a regular hexagon, two adjacent circumradii and the included side forms an equilateral triangle.
∴ The circumradius R of a regular hexagon = length of any side = 6 cm.
Now, we can find out the inradius r , using the Pythagoras theorem.
R2=r2+32
⇒62=r2+32
⇒r2=36−9=27
⇒r=3√3 cm