Question

What is the inradius of a right triangle with a height of 3, base of 4, and a hypotenuse of 5 ?

• A. $1$
• B. $2$
• C. $3$
• D. $1.5$

Answer 1

The correct option is A $1$

We know, Area, A =$\frac{1}{2}bh=\frac{12}{2}=6$

Now, semiperimeter, s = $\frac{a+b+c}{2}=\frac{12}{2}=6$

Thus, $r=\frac{A}{s}=\frac{6}{6}=1$.