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Reaction with Metals

What is the ...

Question

What is the $K_{s p}$ for the process shown below?
$F e {C l}_{3} (s) ⇌ {F e}^{3 +} (a q) + 3 {C l}^{-} (a q)$

[{F e}^{3 +}] {[{C l}^{-}]}^{3}

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\frac{[{F e}^{3 +}] {[{C l}^{-}]}^{3}}{F e {C l}_{3}}

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\frac{1}{[{F e}^{3 +}] 3 [{C l}^{-}]}

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\frac{[{F e}^{3 +}] 3 [{C l}^{-}]}{[F e {C l}_{3}]}

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\frac{[F e {C l}_{3}]}{[{F e}^{3 +}] 3 [{C l}^{-}]}

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Solution

The correct option is A $[{F e}^{3 +}] {[{C l}^{-}]}^{3}$
The given reaction is :-
${F e C l}_{3} (s) ⇌ {F e}^{3} + (a q) + 3 {C l}^{-} (a q)$
At equilibrium,
$K = \frac{[{F e}^{3 +}] {[{C l}^{-}]}^{3}}{[{F e C l}_{3}]}$
But, ${F e C l}_{3}$ is pure solid, so, $[{F e C l}_{3}]$ remains constant
so, $[{F e}^{3 +}] {[{C l}^{-}]}^{3} = K [{F e C l}_{3}]$
$\Rightarrow K s p = [{F e}^{3 +}] {[{C l}^{-}]}^{3}$

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