Question

What is the kinetic energy of 2 mole of gas at 300K?

Answer 1

$KE=\frac{3}{2}RT\times n$

$=\frac{3}{2}\times 1.38\times {10}^{-23}\times 300\times 2\times 6\times {10}^{23}$

$=3\times 1.38\times 6\times 300$

$=7452J$

$=7.452RJ$