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Question

What is the largest number that divides 245 and 1029, leaving remainder 5 in each case ?
  1. 16

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Solution

The correct option is A 16

Since the remainder is 5 in both the cases, we have to subtract 5 from each number.
2455=240 and 10295=1024

Now, we have to find the H.C.F of 240 and 1024.

By Euclid's division lemma,
a=bq+r, 0r<b

Here, a = 1024 and b = 2401024=240×4+64240=64×3+4864=48×1+1648=16×3+0

Therefore, H.C.F is 16.
So, the largest number that divides 245 and 1029 leaving remainder 5 in each case is 16.


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