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Byju's Answer
Standard XII
Chemistry
Molarity
What is the l...
Question
What is the largest number which divides
206
,
368
and
449
and leaves the same remainder in each case?
A
32
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B
48
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C
81
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D
96
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Solution
The correct option is
C
81
Let the remainder in each case be
r
.
So,
206
−
r
,
368
−
r
and
449
−
r
are all divisible by
d
which is the H.C.F. of these numbers.
Theory: H.C.F. of
a
,
b
,
c
=
HCF of
(
b
−
a
)
,
(
c
−
b
)
Using this theory,
HCF of
(
(
368
−
r
)
−
(
206
−
r
)
)
and
(
(
449
−
r
)
−
(
368
−
r
)
)
=
HCF of
(
168
,
81
)
=
81
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