What is the largest value of $x$ that satisfies: $x^{2} + 3 x - 10 = 0$

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Solution

Given equation is:
$x^{2} + 3 x - 10 = 0$
Applying quadratic formula,
$x = \frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}$
$a = 1, b = 3, c = - 10$

$∴ x = \frac{- 3 \pm \sqrt{9 - 4 (1) (- 10)}}{2}$
$∴ x = \frac{- 3 \pm \sqrt{49}}{2}$
$∴ x = - 5, 2$

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