What is the LCM of (2a+3b)2 and (4a2–9b2)
(2a – 3b)
(2a – 3b) (2a +3b) 2
(2a – 3b) (2a +3b)
(2a +3b) 2
(2a+3b)2 = (2a + 3b)(2a + 3b)
(4a2–9b2) = (2a – 3b) (2a + 3b)
Therefore the LCM of (2a+3b)2and(4a2–9b2) is (2a–3b)(2a+3b)(2a+3b)=(2a–3b)(2a+3b)2
Simplify the following : (i)(5a−8b)2−(5a+8b)2 (ii)(2a+3b)2−((2a+3b)(2a−3b)) [4 MARKS]