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Question

What is the LCM of (2a+3b)2 and (4a29b2)


A

(2a – 3b)

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B

(2a – 3b) (2a +3b) 2

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C

(2a – 3b) (2a +3b)

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D

(2a +3b) 2

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Solution

The correct option is B

(2a – 3b) (2a +3b) 2


(2a+3b)2 = (2a + 3b)(2a + 3b)

(4a29b2) = (2a – 3b) (2a + 3b)

Therefore the LCM of (2a+3b)2and(4a29b2) is (2a3b)(2a+3b)(2a+3b)=(2a3b)(2a+3b)2


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