What is the LCM of (x2+5x+6) and (x2+7x+10)
(x + 2)
(x + 3)
(x + 2)(x + 3)
(x + 2)(x + 3)(x + 5)
(x2+5x+6)=(x+2)(x+3)
(x2+7x+10)=(x+2)(x+5)
The LCM of (x2+5x+6)and(x2+7x+10)is(x+2)(x+3)(x+5)
Given
(x2−5x+6)(x2−7x+12)=(x2−x−6)(x2+7x+10), then the value of x is