What is the least number by which 10125 may be divided so that the quotient is a perfect cube?

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Solution

The correct option is B 3
Prime factorization of 10125 gives
$10125 = 5 \times 5 \times 5 \times 3 \times 3 \times 3 \times 3$
By grouping them in triplets, clealy, 10125 must be divided by 3 in order to make it perfect cube.

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