Question

What is the least number of square tiles required to pave the floor of a room $9$ m $99$ cm long and $4$ m $7$ cm broad?

• A. $247$
• B. $277$
• C. $297$
• D. $307$

Answer 1

The correct option is C $297$

Here,

the length of the floor is $9m99cm=999m$

the width of the floor is $4m7cm=407m$

The area of the floor is therefore $(length\ast width)=(999\ast 407)m^2=406593m^2$

Now, for a number of tiles, to completely cover the whole floor, if we divided the whole area by the number of tiles, should give the area of one tile.

On doing so for A, B & D, we get fractional result, which indicates that this number of tiles won't fully cover the floor. For C,

area of one tile is $\frac{406593}{297}=1369m^2={37}^2{m}^2$, which indicates a tile with side $37m$.

Hence, the answer is C.