What is the least number which must be subtracted from $369$ to make it a perfect cube?

8

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26

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Solution

The correct option is B $26$
We know that,
$1^{3} = 1$
$2^{3} = 8$
$3^{3} = 27$
$4^{3} = 64$
$5^{3} = 125$
$6^{3} = 216$
$7^{3} = 343$
$8^{3} = 512$

And $343 < 369 < 512$
So we need to subtract $369 - 343 = 26$ from $369$ to make it a perfect cube.

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What is the least number which must be subtracted from 369 to make it a perfect cube?

The correct option is B 26We know that,13=123=833=2743=6453=12563=21673=34383=512And 343<369<512So we need to subtract 369−343=26 from 369 to make it a perfect cube.

What is the least number which must be subtracted from $369$ to make it a perfect cube?

The correct option is B $26$
We know that,
$1^{3} = 1$
$2^{3} = 8$
$3^{3} = 27$
$4^{3} = 64$
$5^{3} = 125$
$6^{3} = 216$
$7^{3} = 343$
$8^{3} = 512$

And $343 < 369 < 512$
So we need to subtract $369 - 343 = 26$ from $369$ to make it a perfect cube.