What is the least number which, when divided by 5, 6, 7 and 8 gives the remainder 3 but is divisible by 9?

1463

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1573

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1683

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1793

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 1683
L.C.M. of $5, 6, 7 a n d 8 = 35 \times 24 = 840$
Therefore, the required number $= 840 x + 3$ , which is exactly divisible by 9.
For $x = 2$ , it is divisible by 9.
Hence,
Required number $= 840 x + 3 = 840 \times 2 + 3 = 1683$

Suggest Corrections

Similar questions

5, 6, 7

8

3

9

5, 6, 7

8

3

4, 6, 8

9

13

7

A number when divided by by 9 gives 8 as a remainder. What will be the remainder obtained when the same number is divided by 3.

Join BYJU'S Learning Program