Question

What is the least value that should be given to ${}^{\prime }{a}^{\prime }$ so that the number $653a47$ will be divisible by 11?
[2 marks]

• A. 6
• B. 2
• C. 9
• D. 1

Answer 1

The correct option is D 1

In a number, if the difference of the sum of digits at odd places and the sum of its digits at even places, is either 0 or divisible by 11, then the number is divisible by 11.
$\Rightarrow (7+a+5)-(4+3+6)=0$ or a multiple of 11
Equating to zero we get,
$\Rightarrow 12+a-13=0$
$\Rightarrow a-1=0$
$\therefore$ $a=1$
[2 marks]