What is the length of outer boundary of the park shown in the given figure? What will be the total cost of fencing it at the rate of Rs 20 per metre?

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Solution

Length of outer boundary = Perimeter of park = Sum of all sides length = (200 + 300 + 80 + 300 + 200 + 260) m = 1340 m

Also, the rate of fencing per metre = Rs 20

Then, the rate of fencing 1340 metre = 20 $\times$ 1340 = Rs 26800

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What is the length of outer boundary of the park shown in the given figure? What will be the total cost of fencing it at the rate of Rs 20 per metre? There is a rectangular flower bed in the center of the park. Find the cost of manuring the flower bed at the rate of Rs 50 per square metre.

Question 40

Total cost of fencing the park shown in the given figure is ₹55000. Find the cost of fencing per metre.

What is the length of the outer boundary of the park shown in the given figure? What will be the total cost of fencing it at the rate of Rs 20 per metre?

[2 marks]

Q. What is the length of the outer boundary of the park shown in Figure. What will be the total cost of fencing it at the rate of

R s . 20

per meter? There is a rectangular flower bed in the centre of the park. Find the cost of manuring the flower bed at the rate of

R s . 50

per square meter.

The total cost of fencing the park shown in the Figure is ₹55000. Find the cost of fencing per metre.

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What is the length of outer boundary of the park shown in the given figure? What will be the total cost of fencing it at the rate of Rs 20 per metre?

Length of outer boundary = Perimeter of park = Sum of all sides length = (200 + 300 + 80 + 300 + 200 + 260) m = 1340 m Also, the rate of fencing per metre = Rs 20 Then, the rate of fencing 1340 metre = 20 × 1340 = Rs 26800

Length of outer boundary = Perimeter of park = Sum of all sides length = (200 + 300 + 80 + 300 + 200 + 260) m = 1340 m

Also, the rate of fencing per metre = Rs 20

Then, the rate of fencing 1340 metre = 20 $\times$ 1340 = Rs 26800