Question

What is the length of the foot of the perpendicular drawn from the point $P$ $(3,4,5)$

Answer 1

We know that , on x-axis y=0 and z=0.

Hence, point A= ($3,0,0$)

$PA=\sqrt{{\left(3-3\right)}^2+{\left(0-4\right)}^2+{\left(0-5\right)}^2}=\sqrt{0+16+25}=\sqrt{41}$

On the y-axis x=0 and z=0

Point B= ($0,4,0$)

$PB=\sqrt{9+0+25}=\sqrt{34}$

On the z-axis x=0 and y=0

Point C=(0,0,5)

$PC=\sqrt{9+16+0}=\sqrt{25}=5$