What is the length of the largest square tile that can cover the whole floor of a room having length of 96 m and breadth of 50 m.

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Solution

Length of the room = 96m
Breadth of the room = 50 m

The HCF of the 96 and 50 will be size of square tiles.

HCF 96 and 50 = 2m
Area of the room = length × breadth = 96×50=4800 m2

Area of tiles = 2×2 =4m2

So, no. of tiles required = 4800÷4 = 1200 tiles.

ie maximum length of the square tile=2m

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What is the length of the largest square tile that can cover the whole floor of a room having length of 96 m and breadth of 50 m.

Length of the room = 96m Breadth of the room = 50 m The HCF of the 96 and 50 will be size of square tiles. HCF 96 and 50 = 2m Area of the room = length × breadth = 96×50=4800 m*2 Area of tiles = 2×2 =4m*2 So, no. of tiles required = 4800÷4 = 1200 tiles. ie maximum length of the square tile=2m