What is the length of the side of a cube if its lateral surface area is $4 {cm}^{2}$ ?

4 cm

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1 cm

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2 cm

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3 cm

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Solution

The correct option is B 1 cm
$LSA of a cube = 4 a^{2}, where 'a' is the side of the cube.$

$Given, LSA = 4 {cm}^{2} Then, 4 a^{2} = 4 {cm}^{2} \Rightarrow a^{2} = 1 {cm}^{2} \Rightarrow a = \pm \sqrt{1} cm$
$∴ a = 1 cm$
(Length is always positive. Hence $- \sqrt{1} = - 1$ is not considered.)

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If the length of any face diagonal of a cube is 4√2 cm, then the difference between its total surface area and its lateral surface area is:
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Q. If the lateral surface area of a cube is y

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and its side is 20 cm then the value of y is

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What is the length of the side of a cube if its lateral surface area is 4 cm2?

The correct option is B 1 cmLSA of a cube=4a2,where 'a' is the side of the cube. Given, LSA=4 cm2Then, 4a2=4 cm2⇒a2=1 cm2⇒a=±√1 cm ∴a=1 cm (Length is always positive. Hence −√1=−1 is not considered.)

What is the length of the side of a cube if its lateral surface area is $4 {cm}^{2}$ ?

The correct option is B 1 cm
$LSA of a cube = 4 a^{2}, where 'a' is the side of the cube.$

$Given, LSA = 4 {cm}^{2} Then, 4 a^{2} = 4 {cm}^{2} \Rightarrow a^{2} = 1 {cm}^{2} \Rightarrow a = \pm \sqrt{1} cm$
$∴ a = 1 cm$
(Length is always positive. Hence $- \sqrt{1} = - 1$ is not considered.)