What is the locus of the center of a cycle wheel?

line diagonal to the ground

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Concentric circle

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Curved path

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straight line parallel to the ground

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Solution

The correct option is D
straight line parallel to the ground

Locus is a straight line parallel to the road.

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(2 x - 3 y + 4) + k (x - 2 y + 3) = 0, k ϵ R,

(2 x - 3 y + 4) + k (x - 2 y + 3) = 0, k ϵ R,

Locus of the image of the point $(2, 3)$ in the line $(2 x - 3 y + 4) + k (x - 2 y + 3) = 0, k ϵ R$ is a

y^{2} = 4 a (x + a s i n (\frac{x}{a}))

2 d

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