The correct option is D ¬∃x(F(x)∧P(x))
None of my friends are perfect i.e., all of my friends are not perfect
∀x((F(x)→¬P(x))
∀x(¬F(x)∨¬P(x))
¬∃x(F(x)∧P(x))
Alternatively
∃x(F(x)∧P(x)) gives
there exist some of my friends who are perfect.
¬∃x(F(x)∧P(x))
there does not exits any friend who is perfect i.e none of my friends are perfect.
So (d) is correct option.