wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

What is the loss in mass during the change: 3Li7+1H12 2He4+17.25 MeV

A
0.225 amu
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.185 amu
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
0.285 amu
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.385 amu
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 0.185 amu
Total energy change during reaction (given) = 17.25 MeV We know that energy = mass effect × 931 MeV or E = Δm×931
Mass defect (Δm)=E931=17.25931=0.0185amu

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Mass Energy Equivalence
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon