Question

What is the magnetic moment (spin only) and hybridization of central atom in the brown ring complex $\left[Fe\right(H_{2}O{)}_{5}NO]S{O}_4?$

• A. $\sqrt{3}B.M,d^{2}s{p}^3$
• B. $\sqrt{3}B.M,s{p}^3{d}^2$
• C. $\sqrt{15}B.M.,s{p}^3{d}^2$
• D. $\sqrt{15}B.M.,d^{2}s{p}^3$

Answer 1

The correct option is C $\sqrt{15}B.M.,s{p}^3{d}^2$

The brown ring complex is $\left[Fe\right(H_{2}O{)}_{5}NO]S{O}_4$ where $Fe$ is +1.
$F{e}^{+1}=d^7$ configuration have 3 unpaired electron so magnetic moment $\mu =\sqrt{3(3+2)}=\sqrt{15}B.M.$
And here hybridization of Fe is $s{p}^3{d}^2.$