Question

What is the magnifying power of a telescope whose objective and eye - piece have focal length 180 cm and 3 cm respectively?

• A. 50
• B. 40
• C. 30
• D. 60

Answer 1

The correct option is D 60

Here $F=180cm$ and $f=30cm$
$\therefore$ Magnifying power M
$=\frac{F}{f}=\frac{180}{3}=60$