What is the magnitude of axial field due to a bar magnet of length $3$ cm at a distance of $75$ cm from its mid-point if its magnetic moment is $0.6 A m^{2}$ ?

0.013 μ T

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.113 μ T

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.213 μ T

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.313 μ T

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $0.213 μ T$
Here, $m = 0.6 A m^{2}, r = 75 c m = 0.75 m$
$B_{a x i a l} = \frac{μ_{0}}{4 π} . [\frac{2 m}{r^{3}}] = 10^{- 7} \times \frac{2 \times 0.6}{(0.75)^{3}}$
$∴ B_{a x i a l} = 2.13 \times 10^{- 7} T = 0.213 μ T .$

Suggest Corrections

Similar questions

Q. The magnitude of the equatorial magnetic field due to a bar magnet of length

2

cm at a distance of

1

m from its mid-point is (magnetic moment of the bar magnet is

0.60 A m^{2}

)

Q. A short bar magnet has a magnetic moment of

0.48 J T^{- 1}

. The magnitude and direction of magnetic field produced by the magnet at a distance of

10

cm from the centre of the magnet on its axis is

Q. A bar magnet is

0.10 m

long and its pole strength is

120 A m

. Find magnitude of magnetic field at a point on the its axis at a distance

20 c m

from it.

Q. The magnetic field due to a short magnet a point on its axis at distance X cm from the middle point of the magnet is

200 g a u s s

. The magnetic field at a point on the neutral axis at a distance X cm from the middle of the magnet is

A bar magnet is placed with its north pole pointing towards north. The neutral point is at a distance $20 c m$ from the center of the magnet. The net magnetic induction at a distance $10 c m$ on the axial line of the magnet is:

Join BYJU'S Learning Program

What is the magnitude of axial field due to a bar magnet of length 3cm at a distance of 75cm from its mid-point if its magnetic moment is 0.6Am2?

The correct option is A 0.213μTHere, m=0.6Am2,r=75cm=0.75mBaxial=μ04π.[2mr3]=10−7×2×0.6(0.75)3∴Baxial=2.13×10−7T=0.213μT.

What is the magnitude of axial field due to a bar magnet of length $3$ cm at a distance of $75$ cm from its mid-point if its magnetic moment is $0.6 A m^{2}$ ?

The correct option is A $0.213 μ T$
Here, $m = 0.6 A m^{2}, r = 75 c m = 0.75 m$
$B_{a x i a l} = \frac{μ_{0}}{4 π} . [\frac{2 m}{r^{3}}] = 10^{- 7} \times \frac{2 \times 0.6}{(0.75)^{3}}$
$∴ B_{a x i a l} = 2.13 \times 10^{- 7} T = 0.213 μ T .$