Question

What is the magnitude of force required(in $Newton$) to produce a pressure of $37500Pa$ in an area of $300{cm}^2$?

Answer 1

Pressure $P=37500Pa$ Area $A={300cm}^2=3\times {10}^{-2}{m}^2$

Since,

Pressure $P=\frac{Force}{Area}\Rightarrow ForceF=P\times A=37500\times 3\times {10}^{-2}N$

Hence, Force $F=1125N$