What is the magnitude of net force in the given situation? [0.5 marks]

(a) 1 N
(b) 2 N
(c) 5 N
(d) 0.5 N

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Solution

Option (d) 0.5 N
(0.5 marks)

Given:
$F_{1} = 6 N$ towards right
$F_{2} = 5.5 N$ towards left

The forces acting on the object are opposite in direction and different in magnitude.
$∴$ Net force:
$F_{n e t} = F_{1} - F_{2}$
$F_{n e t} = 6 - 5.5 = 0.5 N$

The direction of net force is towards right.

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