What is the main principle of sulphuric acid production by lead chamber process?

Moist

S

in presence of nitrogenous oxides (active catalyst) is oxidized to sulphur trioxide which is oxidised to sulphuric acid

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Moist

S O_{2}

in presence of nitrogenous oxides is oxidized to sulphur monoxide which reacts water to produce sulphuric acid

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Moist

S

in presence of nitrogenous oxides is oxidized to sulphur trioxide which reacts water to produce sulphuric acid

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Moist

S O_{2}

in presence of nitrogenous oxides is oxidized to sulphur trioxide which reacts water to produce sulphuric acid

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Solution

The correct option is D Moist $S O_{2}$ in presence of nitrogenous oxides is oxidized to sulphur trioxide which reacts water to produce sulphuric acid
Lead Chamber process is one of the sulphuric acid production methods which gives only about $50 - 60$ $B e$ grade acid. The main principle behind the process is that the moist $S O_{2}$ (sulphur dioxide) in presence of nitrogenous oxides (active catalyst) is oxidized to sulphur trioxide with the oxygen present in air. Sulphur trioxide is made to react with water to produce sulphuric acid.

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Similar questions

Sulphur trioxide gas is an important precursor to manufacture sulphuric acid. It is produced by the catalytic oxidation of $S O_{2}$ gas. Which of the following are suitable catalysts for the process?

Q. Oxidation of Sulphur to Sulphur trioxide is thermodynamically more favourable than oxidation of Sulphur to Sulphur dioxide – true or false?

Name the oxide of sulphur which reacts with water to give sulphuric acid.

Q. Sulphur oxides combine with water vapour to produce sulphuric acid.

Sulphur trioxide gas is an important precursor to manufacture sulphuric acid. It is produced by the catalytic oxidation of $S O_{2}$ gas. In the contact process, once we obtain $S O_{3} (g)$ , Sulphuric acid is obtained by the hydrolysis of $S O_{3} (g)$ .

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