What is the mass in grams of $17.0$ liters of Nitrogen gas $N_{2}$ at STP?

21.25 g

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28 g

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5.6 g

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25.6 g

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Solution

The correct option is A $21.25 g$
$22.4 L$ volume has $1 m o l e$ of any gas.
$17.0 L$ volume of $N_{2}$ has $\frac{17}{22.4} = 0.75 m o l e s$
Weight of $0.75 m o l e = 0.75 \times 28 = 21.25 g m$

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