What is the mass of $1 m o l e$ of $B e {(O H)}_{2}$ ?

29.03 g

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43.03 g

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52.04 g

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44.83 g

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Solution

The correct option is B $43.03 g$
The molecular formula of Beryllium Hydroxide is $B e (O H)_{2}$
No. of moles $= \frac{Mass}{Molar Mass}$
$1 = \frac{Mass}{Molar Mass}$

$\Rightarrow$ Mass of $B e (O H)_{2} = 9.03 + 2 \times 16 \times 2 \times 1 = 43.03 g$

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