What is the mass of 1 mole of F eSO 4 -7 H 2 O -A- 69-5 gB- 278 gC- 34-75 gD- 139 g

The correct option is B 278 gMass of one mole = 56(Fe) + 32(S) + 4 × 16(O) + 7 × 18(H_2O) = 278g ...

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Standard IX

Chemistry

Molecular Weight

What is the m...

Question

What is the mass of 1 mole of $F e S O_{4} .7 H_{2} O$ ?

69.5 g

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278 g

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34.75 g

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139 g

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Solution

The correct option is B 278 g
Mass of one mole = $56 (F e) + 32 (S) + 4 \times 16 (O) + 7 \times 18 (H_{2} O) = 278 g$

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Similar questions

If the total number of electrons present in a pure sample of $F e S O_{4} . 7 H_{2} O$ is $4.336 \times 10^{26}$
then the total number of moles of oxygen atoms present in $F e S O_{4} .7 H_{2} O$ :

Q. What is the colour of

F e S O_{4} .7 H_{2} O

Q. If the total mass of oxygen present in

F e S O_{4} .7 H_{2} O

176 g

the total number of electrons in

F e S O_{4} .7 H_{2} O

is y

\times 10^{25}

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Q. Calculate the mass of a formula unit of the complex

F e S O_{4} . 7 H_{2} O

in unified atomic mass unit.

Q. Calculate the mass of a formula unit of the complex

F e S O_{4} . 7 H_{2} O

in unified atomic mass unit.

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What is the mass of 1 mole of FeSO4.7H2O?

The correct option is B 278 gMass of one mole = 56(Fe)+32(S)+4×16(O)+7×18(H2O)=278g

What is the mass of 1 mole of $F e S O_{4} .7 H_{2} O$ ?

The correct option is B 278 g
Mass of one mole = $56 (F e) + 32 (S) + 4 \times 16 (O) + 7 \times 18 (H_{2} O) = 278 g$