What is the mass of 4-82 - 1025 molecules of H 2 O in grams-A- 1440-71 gB- 1248-71 gC- 1448-71 gD- 1438-71 g

The correct option is A 1440.71 gNumber of moles of water =Total number of molecules/Avogadro constant=4.82×10^25/6.022× 10^23=80 Therefore, mass of water = N ...

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Standard VIII

Chemistry

Mole Concept

What is the m...

Question

What is the mass of 4.82 x $10^{25}$ molecules of $H_{2} O$ in grams?

1440.71 g

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1448.71 g

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1438.71 g

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1248.71 g

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Solution

The correct option is A 1440.71 g
Number of moles of water $= \frac{Total number of molecules}{Avogadro constant} = \frac{4.82 \times 10^{25}}{6.022 \times 10^{23}} = 80$

Therefore, mass of water = $Number of moles \times Molecular Mass$
$= 80 \times 18 = 1440.71$ g

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Similar questions

What is the mass of 4.82 x $10^{25}$ molecules of $H_{2} O$ in grams?

___ gm. (upto 2 decimal places)

Q. Total mass of

4.82 \times 10^{25}

molecules of water is:

Q. Mass of 4.82 x

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molecules of

H_{2} O

is approximately ____.

Q. Calculate the mass of 12.044 × 10²⁵ molecules of oxygen (O₂).

Q. Which of the following correctly represents

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(i)

2

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H_{2} O

(ii)

20

moles of

H_{2} O

(iii)

6.022 \times 10^{23}

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(iv)

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What is the mass of 4.82 x 1025 molecules of H2O in grams?

The correct option is A 1440.71 gNumber of moles of water =Total number of moleculesAvogadro constant=4.82×10256.022×1023=80 Therefore, mass of water = Number of moles×Molecular Mass =80×18=1440.71 g

What is the mass of 4.82 x $10^{25}$ molecules of $H_{2} O$ in grams?

The correct option is A 1440.71 g
Number of moles of water $= \frac{Total number of molecules}{Avogadro constant} = \frac{4.82 \times 10^{25}}{6.022 \times 10^{23}} = 80$

Therefore, mass of water = $Number of moles \times Molecular Mass$
$= 80 \times 18 = 1440.71$ g