Question

What is the mass of $4g$ atom of$Ag$?

Answer 1

Part one : Introduction of mole and mass

• One gram atom is equal to one mole of the given element.
• The mass is obtained from the product of moles and molar mass of element for one mole.

Part two: Mass of $4g$ atom of Silver$\left(Ag\right)$

• Here, $4g$ atom mean $4$moles of Silver$\left(Ag\right)$
• The mass of $4$ moles of Silver$\left(Ag\right)$ is

$\begin{array}{rcl}mass& =& 4mol\times molarmassofSilver\left(Ag\right)\\ mass& =& 4mol\times 108\frac{g}{mol}\\ mass& =& 432g\end{array}$

Therefore, the mass of $4g$ atom of Silver$\left(Ag\right)$ is $432g$.