What is the mass of $5 m^{3}$ of cement of density $3000 k g / m^{3}$ ?

Open in App

Solution

Density = Mass/Volume
Mass = Density x Volume
Mass = $3000 K g / m^{3} \times 5 m^{3}$ = 15000 Kgs.

Suggest Corrections

Similar questions

Q. Calculate the mass of

8 m^{3}

of cement of density

2000 k g / m^{3}

The breaking stress of a material is 108N/m, density of material is 3000kg/m3
. Find the greatest
length of wire that could hang vertically without breaking. (Pause the video and solve without
looking at the solution).

Q. (a) Define density. What is the SI unit of density?
(b) Define relative density. What is the SI unit of relative density?
(c) The density of turpentine is 840 kg/m³. What will be its relative density? (Density of water = 1000 kg/m³)

What is the density of 5 litres of water having mass 5 kg?

Multiply the following polynomials.

(i) (m³

-

2m + 3)(m⁴

-

2m²+ 3m + 2)

(ii) (5m³

-

2)(m²

-

m + 3)

Join BYJU'S Learning Program

What is the mass of 5m3 of cement of density 3000kg/m3 ?

Density = Mass/Volume Mass = Density x Volume Mass = 3000Kg/m3×5m3 = 15000 Kgs.

What is the mass of $5 m^{3}$ of cement of density $3000 k g / m^{3}$ ?

Density = Mass/Volume
Mass = Density x Volume
Mass = $3000 K g / m^{3} \times 5 m^{3}$ = 15000 Kgs.