What is the mass of $5 m^{3}$ of cement of density $3000 k g / m^{3}$

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Solution

Volume $= 5 m^{3}$
Density $= 3000 k g / m^{3}$
Density of cement $= \frac{m a s s o f c e m e n t}{v o l u m e o f c e m e n t}$
mass of cement $= D e n s i t y o f c e m e n t \times v o l u m e o f c e m e n t$
$= 3000 \times 5 = 15000 k g$

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What is the mass of 5m3 of cement of density 3000 kg/m3

Volume =5m3Density =3000kg/m3Density of cement =mass of cementvolume of cementmass of cement =Density of cement×volume of cement=3000×5=15000kg

What is the mass of $5 m^{3}$ of cement of density $3000 k g / m^{3}$

Volume $= 5 m^{3}$
Density $= 3000 k g / m^{3}$
Density of cement $= \frac{m a s s o f c e m e n t}{v o l u m e o f c e m e n t}$
mass of cement $= D e n s i t y o f c e m e n t \times v o l u m e o f c e m e n t$
$= 3000 \times 5 = 15000 k g$